(1)计算:12?(?2010)0+(12)?1+|?3|.(2)解方程:x2-2x-5=0

(1)计算:12?(?2010)0+(12)?1+|?3|.(2)解方程:x2-2x-5=0.
2025-07-29 19:48:21
推荐回答(1个)
回答1:

(1)原式=2

3
-1+2+
3
=3
3
+1;

(2)∵a=1,b=-2,c=-5,
b2-4ac=(-2)2-4×1×(-5)=24,
∴x=
24
2×1
=
2±2
6
2
=1±
6

∴x1=1+
6
,x2=1-
6