已知m、n满足 |m+2|+ n-4 =0 ,分解因式(x 2 +y 2 )-(mxy+n)

2025-12-13 23:59:31
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回答1:

根据题意得,m+2=0,n-4=0,
解得m=-2,n=4,
∴(x 2 +y 2 )-(mxy+n),
=x 2 +y 2 +2xy-4,
=(x 2 +y 2 +2xy)-4,
=(x+y) 2 -2 2
=(x+y+2)(x+y-2).