2a²+2b²+2c²+2d²-2ab+2cd=22a²+2b²+2c²+2d²-2ab+2cd=2(ad-bc)2a²+2b²+2c²+2d²-2ab+2cd-2ad+2bc=0(a²-2ab+b²)+(c²+2cd+d²)+...=0(a-b)²+(c+d)²+(a-d)²+(b+c)²=0得出a=b=d=-cad-bc=1即 2a²=1a²=0.5abcd=-aaaa=-0.25