（1）原式=3-1+4 3 - 3 =2+3 3 ；（2）原式= x2?1?x2+2x x(x+1) ÷ x(2x?1) (x+1)2 = 2x?1 x(x+1) × (x+1)2 x(2x?1) = x+1 x2 ，∵x满足x2-x-1=0，∴x2=x+1，∴原式= x+1 x+1 =1．
